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24x^2-66x+15=0
a = 24; b = -66; c = +15;
Δ = b2-4ac
Δ = -662-4·24·15
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-66)-54}{2*24}=\frac{12}{48} =1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-66)+54}{2*24}=\frac{120}{48} =2+1/2 $
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